CAS RN 60687-93-6
CAS RN 60687-93-6
IUPAC Name:
3,5,6,8-tetrahydroxy-7-[2-hydroxy-5-(2-hydroxyethyl)phenyl]-9,10-dioxo-9,10-dihydroanthracene-1,2-dicarboxylic acid; 3,6,8-trihydroxy-1-methyl-9,10-dioxo-9,10-dihydroanthracene-2-carboxylic acid; 7-[5-(2-acetamidoethyl)-2-hydroxyphenyl]-3,5,6,8-tetrahydroxy-9,10-dioxo-9,10-dihydroanthracene-1,2-dicarboxylic acid; 7-[5-(2-amino-2-carboxyethyl)-2-hydroxyphenyl]-3,5,6,8-tetrahydroxy-9,10-dioxo-9,10-dihydroanthracene-1,2-dicarboxylic acid
Synonyms:
3,5,6,8-tetrahydroxy-7-[2-hydroxy-5-(2-hydroxyethyl)phenyl]-9,10-dioxoanthracene-1,2-dicarboxylic acid; 3,6,8-trihydroxy-1-methyl-9,10-dioxoanthracene-2-carboxylic acid; 7-[5-(2-acetamidoethyl)-2-hydroxyphenyl]-3,5,6,8-tetrahydroxy-9,10-dioxoanthracene-1,2-dicarboxylic acid; 7-[5-(2-amino-2-carboxyethyl)-2-hydroxyphenyl]-3,5,6,8-tetrahydroxy-9,10-dioxoanthracene-1,2-dicarboxylic acid
Molecular Weight (g/mol):
1887.47
Molecular Formula:
C91H62N2O44
InChi Key:
NGZUCVGMNQGGNA-UHFFFAOYNA-N
SMILES:
CC1=C2C(=O)C3=C(O)C=C(O)C=C3C(=O)C2=CC(O)=C1C(O)=O.OCCC1=CC(=C(O)C=C1)C1=C(O)C2=C(C(O)=C1O)C(=O)C1=CC(O)=C(C(O)=O)C(C(O)=O)=C1C2=O.CC(=O)NCCC1=CC(=C(O)C=C1)C1=C(O)C2=C(C(O)=C1O)C(=O)C1=CC(O)=C(C(O)=O)C(C(O)=O)=C1C2=O.NC(CC1=CC(=C(O)C=C1)C1=C(O)C2=C(C(O)=C1O)C(=O)C1=CC(O)=C(C(O)=O)C(C(O)=O)=C1C2=O)C(O)=O
1
–
1
of
1
results
1
Laccaic Acid from Lacca, TCI America™
CAS: 60687-93-6 Molecular Formula: C91H62N2O44 Molecular Weight (g/mol): 1887.467 MDL Number: MFCD00071249 InChI Key: NGZUCVGMNQGGNA-UHFFFAOYSA-N PubChem CID: 133109320 IUPAC Name: 7-[5-(2-acetamidoethyl)-2-hydroxyphenyl]-3,5,6,8-tetrahydroxy-9,10-dioxoanthracene-1,2-dicarboxylic acid;7-[5-(2-amino-2-carboxyethyl)-2-hydroxyphenyl]-3,5,6,8-tetrahydroxy-9,10-dioxoanthracene-1,2-dicarboxylic acid;3,5,6,8-tetrahydroxy-7-[2-hydroxy-5-(2- SMILES: CC1=C2C(=CC(=C1C(=O)O)O)C(=O)C3=CC(=CC(=C3C2=O)O)O.CC(=O)NCCC1=CC(=C(C=C1)O)C2=C(C3=C(C(=C2O)O)C(=O)C4=CC(=C(C(=C4C3=O)C(=O)O)C(=O)O)O)O.C1=CC(=C(C=C1CCO)C2=C(C3=C(C(=C2O)O)C(=O)C4=CC(=C(C(=C4C3=O)C(=O)O)C(=O)O)O)O)O.C1=CC(=C(C=C1CC(C(=O)O)N)C2=C(C3=C(C(=